3.1317 \(\int (A+B x) (d+e x) (a+c x^2)^3 \, dx\)

Optimal. Leaf size=148 \[ \frac {1}{2} a^3 x^2 (A e+B d)+a^3 A d x+\frac {3}{4} a^2 c x^4 (A e+B d)+\frac {1}{3} a^2 x^3 (a B e+3 A c d)+\frac {1}{7} c^2 x^7 (3 a B e+A c d)+\frac {1}{2} a c^2 x^6 (A e+B d)+\frac {3}{5} a c x^5 (a B e+A c d)+\frac {1}{8} c^3 x^8 (A e+B d)+\frac {1}{9} B c^3 e x^9 \]

[Out]

a^3*A*d*x+1/2*a^3*(A*e+B*d)*x^2+1/3*a^2*(3*A*c*d+B*a*e)*x^3+3/4*a^2*c*(A*e+B*d)*x^4+3/5*a*c*(A*c*d+B*a*e)*x^5+
1/2*a*c^2*(A*e+B*d)*x^6+1/7*c^2*(A*c*d+3*B*a*e)*x^7+1/8*c^3*(A*e+B*d)*x^8+1/9*B*c^3*e*x^9

________________________________________________________________________________________

Rubi [A]  time = 0.21, antiderivative size = 148, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {772} \[ \frac {3}{4} a^2 c x^4 (A e+B d)+\frac {1}{3} a^2 x^3 (a B e+3 A c d)+\frac {1}{2} a^3 x^2 (A e+B d)+a^3 A d x+\frac {1}{7} c^2 x^7 (3 a B e+A c d)+\frac {1}{2} a c^2 x^6 (A e+B d)+\frac {3}{5} a c x^5 (a B e+A c d)+\frac {1}{8} c^3 x^8 (A e+B d)+\frac {1}{9} B c^3 e x^9 \]

Antiderivative was successfully verified.

[In]

Int[(A + B*x)*(d + e*x)*(a + c*x^2)^3,x]

[Out]

a^3*A*d*x + (a^3*(B*d + A*e)*x^2)/2 + (a^2*(3*A*c*d + a*B*e)*x^3)/3 + (3*a^2*c*(B*d + A*e)*x^4)/4 + (3*a*c*(A*
c*d + a*B*e)*x^5)/5 + (a*c^2*(B*d + A*e)*x^6)/2 + (c^2*(A*c*d + 3*a*B*e)*x^7)/7 + (c^3*(B*d + A*e)*x^8)/8 + (B
*c^3*e*x^9)/9

Rule 772

Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegr
and[(d + e*x)^m*(f + g*x)*(a + c*x^2)^p, x], x] /; FreeQ[{a, c, d, e, f, g, m}, x] && IGtQ[p, 0]

Rubi steps

\begin {align*} \int (A+B x) (d+e x) \left (a+c x^2\right )^3 \, dx &=\int \left (a^3 A d+a^3 (B d+A e) x+a^2 (3 A c d+a B e) x^2+3 a^2 c (B d+A e) x^3+3 a c (A c d+a B e) x^4+3 a c^2 (B d+A e) x^5+c^2 (A c d+3 a B e) x^6+c^3 (B d+A e) x^7+B c^3 e x^8\right ) \, dx\\ &=a^3 A d x+\frac {1}{2} a^3 (B d+A e) x^2+\frac {1}{3} a^2 (3 A c d+a B e) x^3+\frac {3}{4} a^2 c (B d+A e) x^4+\frac {3}{5} a c (A c d+a B e) x^5+\frac {1}{2} a c^2 (B d+A e) x^6+\frac {1}{7} c^2 (A c d+3 a B e) x^7+\frac {1}{8} c^3 (B d+A e) x^8+\frac {1}{9} B c^3 e x^9\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.05, size = 135, normalized size = 0.91 \[ \frac {1}{6} a^3 x (3 A (2 d+e x)+B x (3 d+2 e x))+\frac {1}{20} a^2 c x^3 (5 A (4 d+3 e x)+3 B x (5 d+4 e x))+\frac {1}{70} a c^2 x^5 (7 A (6 d+5 e x)+5 B x (7 d+6 e x))+\frac {1}{504} c^3 x^7 (9 A (8 d+7 e x)+7 B x (9 d+8 e x)) \]

Antiderivative was successfully verified.

[In]

Integrate[(A + B*x)*(d + e*x)*(a + c*x^2)^3,x]

[Out]

(a^3*x*(3*A*(2*d + e*x) + B*x*(3*d + 2*e*x)))/6 + (a^2*c*x^3*(5*A*(4*d + 3*e*x) + 3*B*x*(5*d + 4*e*x)))/20 + (
a*c^2*x^5*(7*A*(6*d + 5*e*x) + 5*B*x*(7*d + 6*e*x)))/70 + (c^3*x^7*(9*A*(8*d + 7*e*x) + 7*B*x*(9*d + 8*e*x)))/
504

________________________________________________________________________________________

fricas [A]  time = 0.65, size = 165, normalized size = 1.11 \[ \frac {1}{9} x^{9} e c^{3} B + \frac {1}{8} x^{8} d c^{3} B + \frac {1}{8} x^{8} e c^{3} A + \frac {3}{7} x^{7} e c^{2} a B + \frac {1}{7} x^{7} d c^{3} A + \frac {1}{2} x^{6} d c^{2} a B + \frac {1}{2} x^{6} e c^{2} a A + \frac {3}{5} x^{5} e c a^{2} B + \frac {3}{5} x^{5} d c^{2} a A + \frac {3}{4} x^{4} d c a^{2} B + \frac {3}{4} x^{4} e c a^{2} A + \frac {1}{3} x^{3} e a^{3} B + x^{3} d c a^{2} A + \frac {1}{2} x^{2} d a^{3} B + \frac {1}{2} x^{2} e a^{3} A + x d a^{3} A \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)*(c*x^2+a)^3,x, algorithm="fricas")

[Out]

1/9*x^9*e*c^3*B + 1/8*x^8*d*c^3*B + 1/8*x^8*e*c^3*A + 3/7*x^7*e*c^2*a*B + 1/7*x^7*d*c^3*A + 1/2*x^6*d*c^2*a*B
+ 1/2*x^6*e*c^2*a*A + 3/5*x^5*e*c*a^2*B + 3/5*x^5*d*c^2*a*A + 3/4*x^4*d*c*a^2*B + 3/4*x^4*e*c*a^2*A + 1/3*x^3*
e*a^3*B + x^3*d*c*a^2*A + 1/2*x^2*d*a^3*B + 1/2*x^2*e*a^3*A + x*d*a^3*A

________________________________________________________________________________________

giac [A]  time = 0.17, size = 173, normalized size = 1.17 \[ \frac {1}{9} \, B c^{3} x^{9} e + \frac {1}{8} \, B c^{3} d x^{8} + \frac {1}{8} \, A c^{3} x^{8} e + \frac {1}{7} \, A c^{3} d x^{7} + \frac {3}{7} \, B a c^{2} x^{7} e + \frac {1}{2} \, B a c^{2} d x^{6} + \frac {1}{2} \, A a c^{2} x^{6} e + \frac {3}{5} \, A a c^{2} d x^{5} + \frac {3}{5} \, B a^{2} c x^{5} e + \frac {3}{4} \, B a^{2} c d x^{4} + \frac {3}{4} \, A a^{2} c x^{4} e + A a^{2} c d x^{3} + \frac {1}{3} \, B a^{3} x^{3} e + \frac {1}{2} \, B a^{3} d x^{2} + \frac {1}{2} \, A a^{3} x^{2} e + A a^{3} d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)*(c*x^2+a)^3,x, algorithm="giac")

[Out]

1/9*B*c^3*x^9*e + 1/8*B*c^3*d*x^8 + 1/8*A*c^3*x^8*e + 1/7*A*c^3*d*x^7 + 3/7*B*a*c^2*x^7*e + 1/2*B*a*c^2*d*x^6
+ 1/2*A*a*c^2*x^6*e + 3/5*A*a*c^2*d*x^5 + 3/5*B*a^2*c*x^5*e + 3/4*B*a^2*c*d*x^4 + 3/4*A*a^2*c*x^4*e + A*a^2*c*
d*x^3 + 1/3*B*a^3*x^3*e + 1/2*B*a^3*d*x^2 + 1/2*A*a^3*x^2*e + A*a^3*d*x

________________________________________________________________________________________

maple [A]  time = 0.04, size = 143, normalized size = 0.97 \[ \frac {B \,c^{3} e \,x^{9}}{9}+\frac {\left (A e +B d \right ) c^{3} x^{8}}{8}+\frac {\left (A e +B d \right ) a \,c^{2} x^{6}}{2}+\frac {3 \left (A e +B d \right ) a^{2} c \,x^{4}}{4}+\frac {\left (A d \,c^{3}+3 B e a \,c^{2}\right ) x^{7}}{7}+A \,a^{3} d x +\frac {\left (A e +B d \right ) a^{3} x^{2}}{2}+\frac {\left (3 A d a \,c^{2}+3 B e \,a^{2} c \right ) x^{5}}{5}+\frac {\left (3 A d \,a^{2} c +B e \,a^{3}\right ) x^{3}}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*x+A)*(e*x+d)*(c*x^2+a)^3,x)

[Out]

1/9*B*c^3*e*x^9+1/8*c^3*(A*e+B*d)*x^8+1/7*(A*c^3*d+3*B*a*c^2*e)*x^7+1/2*a*c^2*(A*e+B*d)*x^6+1/5*(3*A*a*c^2*d+3
*B*a^2*c*e)*x^5+3/4*a^2*c*(A*e+B*d)*x^4+1/3*(3*A*a^2*c*d+B*a^3*e)*x^3+1/2*a^3*(A*e+B*d)*x^2+a^3*A*d*x

________________________________________________________________________________________

maxima [A]  time = 0.53, size = 154, normalized size = 1.04 \[ \frac {1}{9} \, B c^{3} e x^{9} + \frac {1}{8} \, {\left (B c^{3} d + A c^{3} e\right )} x^{8} + \frac {1}{7} \, {\left (A c^{3} d + 3 \, B a c^{2} e\right )} x^{7} + \frac {1}{2} \, {\left (B a c^{2} d + A a c^{2} e\right )} x^{6} + A a^{3} d x + \frac {3}{5} \, {\left (A a c^{2} d + B a^{2} c e\right )} x^{5} + \frac {3}{4} \, {\left (B a^{2} c d + A a^{2} c e\right )} x^{4} + \frac {1}{3} \, {\left (3 \, A a^{2} c d + B a^{3} e\right )} x^{3} + \frac {1}{2} \, {\left (B a^{3} d + A a^{3} e\right )} x^{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)*(c*x^2+a)^3,x, algorithm="maxima")

[Out]

1/9*B*c^3*e*x^9 + 1/8*(B*c^3*d + A*c^3*e)*x^8 + 1/7*(A*c^3*d + 3*B*a*c^2*e)*x^7 + 1/2*(B*a*c^2*d + A*a*c^2*e)*
x^6 + A*a^3*d*x + 3/5*(A*a*c^2*d + B*a^2*c*e)*x^5 + 3/4*(B*a^2*c*d + A*a^2*c*e)*x^4 + 1/3*(3*A*a^2*c*d + B*a^3
*e)*x^3 + 1/2*(B*a^3*d + A*a^3*e)*x^2

________________________________________________________________________________________

mupad [B]  time = 0.07, size = 140, normalized size = 0.95 \[ x^3\,\left (\frac {B\,e\,a^3}{3}+A\,c\,d\,a^2\right )+x^7\,\left (\frac {A\,d\,c^3}{7}+\frac {3\,B\,a\,e\,c^2}{7}\right )+x^5\,\left (\frac {3\,B\,e\,a^2\,c}{5}+\frac {3\,A\,d\,a\,c^2}{5}\right )+\frac {a^3\,x^2\,\left (A\,e+B\,d\right )}{2}+\frac {c^3\,x^8\,\left (A\,e+B\,d\right )}{8}+A\,a^3\,d\,x+\frac {B\,c^3\,e\,x^9}{9}+\frac {3\,a^2\,c\,x^4\,\left (A\,e+B\,d\right )}{4}+\frac {a\,c^2\,x^6\,\left (A\,e+B\,d\right )}{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + c*x^2)^3*(A + B*x)*(d + e*x),x)

[Out]

x^3*((B*a^3*e)/3 + A*a^2*c*d) + x^7*((A*c^3*d)/7 + (3*B*a*c^2*e)/7) + x^5*((3*A*a*c^2*d)/5 + (3*B*a^2*c*e)/5)
+ (a^3*x^2*(A*e + B*d))/2 + (c^3*x^8*(A*e + B*d))/8 + A*a^3*d*x + (B*c^3*e*x^9)/9 + (3*a^2*c*x^4*(A*e + B*d))/
4 + (a*c^2*x^6*(A*e + B*d))/2

________________________________________________________________________________________

sympy [A]  time = 0.09, size = 182, normalized size = 1.23 \[ A a^{3} d x + \frac {B c^{3} e x^{9}}{9} + x^{8} \left (\frac {A c^{3} e}{8} + \frac {B c^{3} d}{8}\right ) + x^{7} \left (\frac {A c^{3} d}{7} + \frac {3 B a c^{2} e}{7}\right ) + x^{6} \left (\frac {A a c^{2} e}{2} + \frac {B a c^{2} d}{2}\right ) + x^{5} \left (\frac {3 A a c^{2} d}{5} + \frac {3 B a^{2} c e}{5}\right ) + x^{4} \left (\frac {3 A a^{2} c e}{4} + \frac {3 B a^{2} c d}{4}\right ) + x^{3} \left (A a^{2} c d + \frac {B a^{3} e}{3}\right ) + x^{2} \left (\frac {A a^{3} e}{2} + \frac {B a^{3} d}{2}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)*(e*x+d)*(c*x**2+a)**3,x)

[Out]

A*a**3*d*x + B*c**3*e*x**9/9 + x**8*(A*c**3*e/8 + B*c**3*d/8) + x**7*(A*c**3*d/7 + 3*B*a*c**2*e/7) + x**6*(A*a
*c**2*e/2 + B*a*c**2*d/2) + x**5*(3*A*a*c**2*d/5 + 3*B*a**2*c*e/5) + x**4*(3*A*a**2*c*e/4 + 3*B*a**2*c*d/4) +
x**3*(A*a**2*c*d + B*a**3*e/3) + x**2*(A*a**3*e/2 + B*a**3*d/2)

________________________________________________________________________________________